Re: php variables in a backtick command
| From: | Sebastian | Date: | Sun, 12 Dec 2004 01:39:23 +0000 |
| Subject: | Re: php variables in a backtick command | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-204079@lists.php.net to get a copy of this message | ||
well $user['password'] has no double quotes around it.
----- Original Message -----
From: "Jonathan Duncan" <jonathan@nacnud.com>
To: <php-general@lists.php.net>
Sent: Saturday, December 11, 2004 8:09 PM
Subject: [PHP] php variables in a backtick command
> I am trying to run a shell command with backticks. However, I get a parse
> error. Is it because I have an array variable in there?
>
> $result =
`adduser -l=$dist_id -p=$user['password'] --f="$user['name_first']
> $user['name_last']"`;
>
> Do I need to assign the value to a regular variable before I put it in
> there? Like this?
>
> $pword=$user['password']
> $fname =$user['name_first']
> $lname =$user['name_last']
> $result =
adduser -l=$dist_id -p=$pword --f="$fname
> $lname";
>
> Thanks,
> Jonathan
>
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