Re: Reg Expression Search

Sorry Lars, the last message I wrote to you. figured it out. it was easy >> $done = str_replace("\\", "/", $realVal); "Lars Torben Wilson" <torben@pinc.com> wrote in message news:14828.1580.959795.972075@shanna.outlander.ca... > Scott Mebberson writes: > > Hi Guys, > > > > I have real problems with reg exps. I hate them. > > > > I need to do a search on string that will look like this "C:\temp\bg.gif" > > and I want to take from the end of string up until the first backslash. The > > var $realVal contains the string. So I can either take it from --\[*].gif-- > > or --\[*].jpg-- > > > > thanks for all help > > > > scott. > > Did you mean the first backslash as in the first backslash from the > left, or from the right? :) > > If from the right, then it looks like you're trying to just get the > filename, in which case basename() should help: > > http://www.php.net/manual/function.basename.php > > If from the left, then I think the easiest way would probably be with > something like this: > > substr($path, strpos($path, '\\') + 1) . "\n"; > > Just on a side note, be careful when using strings with backslashes in > them: if you use double-quotes with them, weird things can happen if > PHP interprets the backslashes to mean escape sequences. For example, > if you do 'echo "C:\temp\bg.gif";', you get: > > C: emp\bg.gif > > as ouput, since PHP thinks the \t means 'tab'. > > > Cheers, > > Torben > > -- > +----------------------------------------------------------------+ > |Torben Wilson <torben@php.net> Netmill iTech| > |http://www.coastnet.com/~torben > http://www.netmill.fi| > |Ph: 1 250 383-9735 torben@netmill.fi| > +----------------------------------------------------------------+ > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >