warning

From: Date: Tue, 17 Oct 2000 11:47:43 +0000
Subject: warning
Groups: php.general 
Request: Send a blank email to php-general+get-20604@lists.php.net to get a copy of this message
Hello people! I have a problem with mysterious warning.. I have following code: $sql = "select * from some_table where ID=$ID"; $results = mysql_query($sql); $array = mysql_fetch_rows($results); . . . above code is working perfectly, but it gives following warning: Warning: Supplied argument is not a valid MySQL result resource in ./mysql.php3 on line 166 I can't seem to find anything wrong.. Please let me know if you have encountered such warning. Again, the code seems to be working fine and generating correct outputs. Thanks! Tony

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