RE: [PHP] warning

use mysql_error() after the mysql_query() call, you obviously have a mysql error somewhere. > -----Original Message----- > From: hennink@patrijs.max.nl [mailto:hennink@patrijs.max.nl] > Sent: 17 October 2000 14:55 > To: tony > Cc: php-general@lists.php.net > Subject: Re: [PHP] warning > > > Well, > > if you're sure the code is working fine just ignore the errormessage. > Another trick maybe setting the errorlevel in PHP to a lower level. > error_reporting(1); will work for that page, or try to edit your php.ini. > > Tijmen > On Tue, 17 Oct 2000, tony wrote: > > > Hello people! > > > > I have a problem with mysterious warning.. > > I have following code: > > > > $sql = "select * from some_table where ID=$ID"; > > $results = mysql_query($sql); > > $array = mysql_fetch_rows($results); > > . > > . > > . > > above code is working perfectly, but it gives following warning: > > Warning: Supplied argument is not a valid MySQL result resource in > > ./mysql.php3 on line 166 > > I can't seem to find anything wrong.. Please let me know if you have > > encountered such warning. > > Again, the code seems to be working fine and generating correct outputs. > > > > > > Thanks! > > > > > > Tony > > > > -- > Customer: I'm running Windows '98 > Tech: Yes. > Customer: My computer isn't working now. > Tech: Yes, you said that. > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >