RE: [PHP] Beginner's attempt fails

line break woes: I imagine that the line break did work, if you go view your source. However, a \n != <BR> when html is rendered. > -----Original Message----- > From: Michael Talbot-Wilson [mailto:mtw@birdseye.view.net.au] > Sent: Tuesday, October 17, 2000 11:31 AM > To: php-general@lists.php.net > Subject: [PHP] Beginner's attempt fails > > > Well, in the end I got the php 4.0.2 module compiled into Apache > 1.3.12 on Linux. But in the second little document I wrote the > linefeed escape doesn't work. The '\n' disappears from the text > but the lines don't get broken. See output below, and the pgp > that produced it further below. > > Is there something here that I've failed to understand? (The > choice of browser, Netscape/Linux, Lynx/Linux, Microsoft > browser, doesn't make any difference.) > > --Mike > > ----------------------------------------------------------------- > > Here comes php. > > Hello from php. This should be the second line. And this should be the > third. And this the fourth. > > ----------------------------------------------------------------- > > <?xml version="1.0" encoding="ISO-8859-1"?> > <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" > > "http://www.w3.org/TR/xhtml1/DTD/strict.dtd"> > <html > xmlns="http://www.w3.org/1999/xhtml" > xml:lang="en" lang="en"> > <head> > <title>Simple PHP</title> > <meta http-equiv="Content-type" > content='text/html; charset="ISO-8859-1"' > /> > </head> > <body> > > <p>Here comes php.</p> > > <p> > <?php > echo("Hello from php.\n"); > echo "This should be the second line.\n"; > echo "And this should be the third.\n"; > echo "And this the fourth.\n"; > ?> > </p> > > </body> > </html> > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net