Re: Skipping function arguments!

From:	Marek Kilimajer	Date:	Thu, 28 Apr 2005 12:26:28 +0000
Subject:	Re: Skipping function arguments!
References:	1 2 3	Groups:	php.general
Request:	Send a blank email to php-general+get-214079@lists.php.net to get a copy of this message

Bostjan Skufca @ domenca.com wrote:

function add ($a=1, $b=2, $c=3) {
         return $a + $b + $c;
} add(1, null, 1); will do just fine

returns 2, OP wants 4 IMO

r., Bostjan On Thursday 28 April 2005 14:16, Marek Kilimajer wrote:
Vedanta Barooah wrote:
Hello All, Cosider this : function add($a=1,$b=2,$c=3){
       return $a + $b + $c;
} how do i skip the second argument while calling the function, is there a process like this: echo add(1,,1); # where i expect 2 to be printed,
php does not support this. you can workaround this using: function add($a = null,$b = null, $c = null){ if(is_null($a)) $a = 1; if(is_null($b)) $b = 2; if(is_null($c)) $c = 3;
        return $a + $b + $c;
} add(1, null, 1);