Re: Skipping function arguments!

Vedanta Barooah wrote:

btw! saying: add($a=null,$b=null,$c=null) is as good as saying: add($a,$b,$c)

No, it's not. Because in this case $a, $b and $c are all uninitialized variables and (if this is a function definition) then you *have* to supply $a $b and $c parameters. Even if you were just calling add() this wouldn't be wise. Consider the possibility that your server uses register_globals. In that case I can browse to: http://yoursite.com/yourpage.php?a=25&b=20&c=1234567890 Not to mention the code injection possibilities.

thanks, vedanta On 4/28/05, Vedanta Barooah <vedanta.barooah@gmail.com> wrote:

Well that was simple, but this is what i am trying to solve: if you refer to the php documentation for ldap_open() function it says: resource ldap_search ( resource link_identifier, string base_dn, string filter [, array attributes [, int attrsonly [, int sizelimit [, int timelimit [, int deref]]]]]) if you look at the 4th and the 6th arguments to the function attributes is an array while sizelimit is an int, i want to pass the sixth element without passing the 4th and the 5th ... how do i do that?? i tried these options: # this does not work, $rs=ldap_search($con,"o=vodoo.com","(objectClass*)",array(),0,500);

$rs = ldap_search($con, "o=vodoo.com", "(objectClass*)", null, null, 500);

# this wont works :(( $rs=ldap_search($con,"o=vodoo.com","(objectClass*)",' ',0,500); # this also goofs! $rs=ldap_search($con,"o=vodoo.com","(objectClass*)",NULL,0,500); here that 5th arg works if i pass a zero as ... 0 means the default behaviour!! any ideas ... clues ? Thanks, Vedanta Barooah