Re: Re: x years old
| From: | Colin Ross | Date: | Sun, 03 Jul 2005 00:12:35 +0000 |
| Subject: | Re: Re: x years old | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-218035@lists.php.net to get a copy of this message | ||
and for completeness of the topic, ceil() will round fractions up.
i.e.
ceil(16.00001) = 17
ceil(16.00000) = 16
<attempted-humor>
I think the Credit Card Industry using ceil() alot ;P
</attempted-humor>
On 7/2/05, Jasper Bryant-Greene <jasper@bryant-greene.name> wrote:
>
> Ryan A wrote:
> > Hey guys,
> > This is the code I am using to display a persons age from the mysql db:
> >
> > $day1=strtotime($age);
> > $day2 = strtotime(date("Y-m-d"));
> > $dif_s = ($day2-$day1);
> > $dif_d = ($dif_s/60/60/24);
> > $age = round(($dif_d/365.24));
> >
> > but when someone entered their birth day($age) as 1988-07-06 it is
> showing
> > it as
> > 17 years old instead of 16...any idea whats wrong in the above code?
>
> Use floor() instead of round(). Using the round() function will round
> anyone whose age is above 16.5 to 17, while floor() always rounds down.
>
> Jasper
>
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