Re: x years old

* "Ryan A" <ryan@coinpass.com>: > This is the code I am using to display a persons age from the mysql db: > > $day1=strtotime($age); > $day2 = strtotime(date("Y-m-d")); Just to be pedantic... just use time() for the above statement; no reason to do extra work here. (date() will actually call time() anyways) > $dif_s = ($day2-$day1); > $dif_d = ($dif_s/60/60/24); > $age = round(($dif_d/365.24)); And, as someone else mentioned, you want to do floor() here, as somebody is 16 until their 17th birthday. -- Matthew Weier O'Phinney Zend Certified Engineer http://weierophinney.net/matthew/