Re: Simple Question

From: Date: Wed, 25 Oct 2000 20:08:07 +0000
Subject: Re: Simple Question
Groups: php.general 
Request: Send a blank email to php-general+get-21917@lists.php.net to get a copy of this message
To suppress errors prepend an @ sign in from of the mysql command i.e. $result = @mysql_query($sql,$db); $result will only be 0 (false) if you have a syntax error in the sql statement. So if you want to see if you have any matches, use $currentMatches = mysql_num_rows($result); >>> "Chris" <php_list@ibcnetwork.net> 10/23 12:41 PM >>> Hi, I looked in the manual but can't find anything to help. How do I repress mysql errors from displaying? Ex: $strsql = "SELECT myval FROM table where date = '$strdte'"; $result = mysql_db_query("db",$strsql); How can I see if $result is valid? When I do echo $result, it allways prints the number 2, whether is finds data or not. If not it give me the error that mysql can jumpt to row 0 on the next statement which is: $strmydte = mysql_result($result,"myval"); I need to see if there is a result before I reach the above line so I can prevent the error display and do something else. Thanks, Chris

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