Re: undefined variable

From: Date: Sat, 29 Apr 2006 19:57:07 +0000
Subject: Re: undefined variable
References: 1  Groups: php.general 
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2006/4/29, Smart Software <info@smart-software.org>:
code below shows all records from products table with an textbox and an order button for each record <? $query1 = mysql_query("SELECT * FROM products "); while ($rowType = mysql_fetch_array($query1)) { ?> <table width="500" border="0"> <tr class="largeheader"> <td width="40%"><? echo "$rowType[0]"; ?></a> </td> <td width="10%"><?php echo "$rowType[1]"; ?></td> <td width="10%"><input name="quantity" type="text" value="1" size="1" maxlength="3"></td> <td width="40%"> <a href="<? echo "products.php?cat=$cat&toevoegen=1&id=$rowType[7]"; ?>"><img src="images/bestel1.gif" border="0"></a></td> </tr> <?php } ?> </table> if someone presses the button, an item will be ordered. How can i add the content of the textbox? i tried this: <td width="40%"> <a href="<? echo "products.php?cat=$cat&quantity=$quantity&toevoegen=1&id=$rowType[7]"; ?>"><img src="images/bestel1.gif" border="0"></a></td> but all i get is an error telling me there is a undefined varable
Can you post what the error looks like? thanx for all help
N. Karademir -- PHP General Mailing List ( http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php


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