Re: undefined variable

thanx all for the reply. Yes, i am new to PHP I am a c++ programmer and now i am trying to learn php. i guess i did not explain the problem correct. the code is generating an textbox for each record. while(query )//here the query is opened { <table "> <tr> <td ><?php query->name ?> </td> // record from database <td > Please fill in your age:</td> //text <td "><input name="age" type="text" </td> //textbox, <td ><a href="<? echo "otherform.php?age=PLACE_HERE_THE_VALUE_FROM_QUANTITY_TEXTBOX&name=query->name"; ?> "</td> </tr> </table> } how can i get the value from the textbox? i don't have form tag if i have 50 records, there are 50 textboxes named "age" right? ""Smart Software"" <info@smart-software.org> schreef in bericht news:11.4A.18514.B0343544@pb1.pair.com... > code below shows all records from products table with an textbox and an > order button for each record > > <? $query1 = mysql_query("SELECT * FROM products "); > while ($rowType = mysql_fetch_array($query1)) > { ?> > <table width="500" border="0"> > <tr class="largeheader"> > <td width="40%"><? echo "$rowType[0]"; ?></a> > </td> > <td width="10%"><?php echo "$rowType[1]"; ?></td> > <td width="10%"><input name="quantity" type="text" > value="1" size="1" > maxlength="3"></td> > <td width="40%"> <a href="<? echo > "products.php?cat=$cat&toevoegen=1&id=$rowType[7]"; ?>"><img > src="images/bestel1.gif" border="0"></a></td> > </tr> > > <?php > } > ?> > </table> > > > > if someone presses the button, an item will be ordered. > > How can i add the content of the textbox? > i tried this: > <td width="40%"> <a href="<? echo > "products.php?cat=$cat&quantity=$quantity&toevoegen=1&id=$rowType[7]"; > ?>"><img src="images/bestel1.gif" > border="0"></a></td> > > but all i get is an error telling me there is a undefined varable > > > > thanx for all help > N. Karademir