Re: When is "z" != "z" ?
| From: | Robert Cummings | Date: | Tue, 06 Jun 2006 16:46:57 +0000 |
| Subject: | Re: When is "z" != "z" ? | ||
| References: | 1 2 3 4 5 6 7 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-237465@lists.php.net to get a copy of this message | ||
On Tue, 2006-06-06 at 09:46, Martin Alterisio wrote:
> 2006/6/6, Robert Cummings <robert@interjinn.com>:
>
> > In C++ they do leave it to the coder, and well, we all know what a mess
> > it can be deciphering overloaded operators in C++ (or maybe we ALL
> > don't). At any rate, the PHP overlords made a choice, and IMHO the best
> > choice. For such a fringe issue I don't see what the argument is all
> > about. If you want the functionality you get in C by incrementing a
> > char, then use the chr() function on an integer.
> >
> >
> You're right about ++ operator not to be considered a math operator, my
> mistake. What I should have said is that the usual connotation and expected
> behaviour of ++ and the comparison operators is to give iteration
> capabilities to a certain data type, as used in a for statement. For that to
> happen certain constrains must be true for these operators, one of them
> being: any < ++any, which is not true for the way these operators behave in
> php.
You must have missed this post:
http://marc.theaimsgroup.com/?l=php-general&m=114945456908350&w=2
Cheers,
Rob.
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