Re: When is "z" != "z" ?

2006/6/6, Robert Cummings <robert@interjinn.com>:

On Tue, 2006-06-06 at 09:46, Martin Alterisio wrote: 2006/6/6, Robert Cummings <robert@interjinn.com>:

In C++ they do leave it to the coder, and well, we all know what a

mess

it can be deciphering overloaded operators in C++ (or maybe we ALL don't). At any rate, the PHP overlords made a choice, and IMHO the

best

choice. For such a fringe issue I don't see what the argument is all about. If you want the functionality you get in C by incrementing a char, then use the chr() function on an integer.

You're right about ++ operator not to be considered a math operator, my mistake. What I should have said is that the usual connotation and expected behaviour of ++ and the comparison operators is to give iteration capabilities to a certain data type, as used in a for statement. For that to happen certain constrains must be true for these operators, one of them being: any < ++any, which is not true for the way these operators behave in php. You must have missed this post: http://marc.theaimsgroup.com/?l=php-general&m=114945456908350&w=2 Yes, I haven't read that post. That algorithm has an error, an overflow on a

signed char, and that's implementation issue not a design issue. PS: It's a little bit rude to say "you *must* have missed" but I understand that it wasn't your intention.