Re: Re: A variable inside a variable?

You were on the right track, but this isn't going to work.. for a couple reasons: $var = 1; # this is fine $var2 = "$var"; # $var2 == 1 at this point echo $$var2; # you're going to echo $1 Putting $var in double quotes makes PHP evaluate it before assigning it to $var2, so you won't get $var but the value of $var (1). If you did use single quotes, you'd get this: $var = 1; # this is fine $var2 = '$var'; # $var2 == '$var' (literal) echo $$var2; # you're going to echo $$var It seems like you might get $var2 evaluate to $var.. then with $$var have it evaluate to 1, but doesn't look like PHP digs that deeply. When I ran it, I got NULL back. This might be what you were aiming for: $var = 1; # this is fine $var2 = 'var'; # remove the $.. then you can use single or double quotes echo $$var2; # $var == var, $var == 1, this should output correctly Good lesson in 'gotchas' though. -TG = = = Original message = = = $var=1; $var2="$var"; echo $$var2; It~ll echo the $var~s value. Hope it~ll help you. ___________________________________________________________ Sent by ePrompter, the premier email notification software. Free download at http://www.ePrompter.com.