Re: Re: A variable inside a variable?

Please excuse-me. That $ was putted by mistake. I´sorry... <tg-php@gryffyndevelopment.com> escreveu na mensagem news:FF.F9.44237.05430A44@pb1.pair.com... > You were on the right track, but this isn't going to work.. for a couple > reasons: > > $var = 1; # this is fine > $var2 = "$var"; # $var2 == 1 at this point > echo $$var2; # you're going to echo $1 > > Putting $var in double quotes makes PHP evaluate it before assigning it to > $var2, so you won't get $var but the value of $var (1). > > If you did use single quotes, you'd get this: > > $var = 1; # this is fine > $var2 = '$var'; # $var2 == '$var' (literal) > echo $$var2; # you're going to echo $$var > > It seems like you might get $var2 evaluate to $var.. then with $$var have > it evaluate to 1, but doesn't look like PHP digs that deeply. When I ran > it, I got NULL back. > > This might be what you were aiming for: > > $var = 1; # this is fine > $var2 = 'var'; # remove the $.. then you can use single or double quotes > echo $$var2; # $var == var, $var == 1, this should output correctly > > Good lesson in 'gotchas' though. > > -TG > > = = = Original message = = = > > $var=1; > $var2="$var"; > echo $$var2; > > It~ll echo the $var~s value. > > Hope it~ll help you. > > > ___________________________________________________________ > Sent by ePrompter, the premier email notification software. > Free download at http://www.ePrompter.com.