Re: pattern containing single quote in IF statement

I tried that also but it didnt work. if($_GET['query']=="some'u'all") { filter($query);} I still get the same error. ""Jahangir"" <jahan9@gmail.com> wrote in message news:38.50.35414.C3021954@pb1.pair.com... > I am stuck at a wierd problem. I am trying to do comparision between a > "query string" and a "string value". the string consists of some > diacriticals and single quotes. > But when i try to escape the single quotes using backshash (\) it doesnt > work. and when i try to use it inside a double quote preg_replace() doesnt > recognise the code. > why is php not comaparing string with single quotes?? > > here is the code: > if($_GET['query']==new) > { filter($query);} > elseif($_GET['query']==some'u'all) > { filter($query);} > elseif($_GET['query']==all'u'ppl) > { filter($query);} > > function filter($query) > { > $pattern = array > ('/new/','/some'u'all/','/all'u'ppl/'); > $rep = array ("new way","Some of you all ","all of you"); > $op = preg_replace($pattern,$rep,$_GET['query']); > echo "<br>new value $op"; > } > > > also i wanted to just clarify is there a way of using multiple OR's in the > same "if" condition > i.e if(($_GET['query]')==new||newday||newtime||newbeginning||newthing) > { > // fn here; > }