Re: Re: pattern containing single quote in IF statement

First of all, I strongly feel that you should have double quotes around the string you like to compare with (e.g. "new"). Otherwise, you are comparing against a string but to something else (integer ?). Without quotes, PHP will throw an error (not sure if it will throw a fatal error or something else). Second, do a var_dump on $_GET['query']. What do you get? (white space before, after the string? encodes quotes?) You may also look at the function strcasecmp, which is little more elegant than your solution, in my opinion. Regarding your question about "multiple OR", I would do something like: $things_to_look_for = array ( "new, "newday" ... and so on); if ( in_array ( $_GET['query'], $things_to_look_for ) ) { // do some stuff } /frank 26 dec 2006 kl. 14.42 skrev Jahangir:

I tried that also but it didnt work. if($_GET['query']=="some'u'all") { filter($query);} I still get the same error. ""Jahangir"" <jahan9@gmail.com> wrote in message news:38.50.35414.C3021954@pb1.pair.com...

I am stuck at a wierd problem. I am trying to do comparision between a "query string" and a "string value". the string consists of some diacriticals and single quotes. But when i try to escape the single quotes using backshash (\) it doesnt work. and when i try to use it inside a double quote preg_replace() doesnt recognise the code. why is php not comaparing string with single quotes?? here is the code: if($_GET['query']==new) { filter($query);} elseif($_GET['query']==some'u'all) { filter($query);} elseif($_GET['query']==all'u'ppl) { filter($query);} function filter($query) { $pattern = array ('/new/','/some'u'all/','/all'u'ppl/'); $rep = array ("new way","Some of you all ","all of you"); $op = preg_replace($pattern,$rep,$_GET['query']); echo "<br>new value $op"; } also i wanted to just clarify is there a way of using multiple OR's in the same "if" condition i.e if(($_GET['query]')==new||newday||newtime||newbeginning||newthing) { // fn here; }

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