Re: glob(path_pattern, GLOB_ONLYDIR)

Al wrote: > I thought the "." had meaning since the manual user notes used it it means a literal dot, many people assume that glob expressions use the same syntax as regular expressions but this is not the case. > > Definitely, my php is version 4.4.4; it's on a virtual host. > > I found the glob file for the GNU C Library and GLOB_ONLYDIR doesn't > seem to be defined correctly, the file appears to rather old. > > I used the numerical value "8196" and it works fine. I'm a little > reluctant to use the numerical value as I want my code to be generally > universal. Maybe the numerical value is safer anyhow. What do you think? you might consider something like this: if (!defined('GLOB_ONLYDIR')) define('GLOB_ONLYDIR', 8196); I doubt that the numeric value will ever change btw. > > I can alternatively just filter out the files in a second step. that seems like a lesser solution. > > Al............. > > > > Jim Lucas wrote: >> Al wrote: >>> I can't use flag "GLOB_ONLYDIR" to work on a Linux, php4.4.4. I only >>> want the dirs. >>> >>> This works; sort of: >>> print_r(glob('../*',)); //It lists all the files AND directories. >>> Yet it seems to ignore the lack of ".*" and finds xxx.yyy. That's OK, >>> I can delete the files >> remember this is linux you are talking about, not windows. >> >> A '*' means anything, including a '.' >> >> >>> >>> This fails: >>> print_r(glob('../*', GLOB_ONLYDIR)); >> well, double check your php version, because this should be built in >> whit the version that you are running. >> >>> >>> And I get: "Warning: glob() expects parameter 2 to be long, string >>> given in foo" >>> >>> I can't find anything in the manual or when Googling. >>> >>> Anyone can explain this for me? >>> >