Re: glob(path_pattern, GLOB_ONLYDIR)

It doesn't on my Linux system glob("../path/*"); shows files and dirs; foo.ext and dirs Exactly the same as glob("../path/*.*"); I thought using just plain "*" would ignore files; but, it doesn't. Jochem Maas wrote:

Al wrote:

I thought the "." had meaning since the manual user notes used it

it means a literal dot, many people assume that glob expressions use the same syntax as regular expressions but this is not the case.

Definitely, my php is version 4.4.4; it's on a virtual host. I found the glob file for the GNU C Library and GLOB_ONLYDIR doesn't seem to be defined correctly, the file appears to rather old. I used the numerical value "8196" and it works fine. I'm a little reluctant to use the numerical value as I want my code to be generally universal. Maybe the numerical value is safer anyhow. What do you think?

you might consider something like this: if (!defined('GLOB_ONLYDIR')) define('GLOB_ONLYDIR', 8196); I doubt that the numeric value will ever change btw.

I can alternatively just filter out the files in a second step.

that seems like a lesser solution.

Al............. Jim Lucas wrote:

Al wrote:

I can't use flag "GLOB_ONLYDIR" to work on a Linux, php4.4.4. I only want the dirs. This works; sort of: print_r(glob('../*',)); //It lists all the files AND directories. Yet it seems to ignore the lack of ".*" and finds xxx.yyy. That's OK, I can delete the files

remember this is linux you are talking about, not windows. A '*' means anything, including a '.'

This fails: print_r(glob('../*', GLOB_ONLYDIR));

well, double check your php version, because this should be built in whit the version that you are running.

And I get: "Warning: glob() expects parameter 2 to be long, string given in foo" I can't find anything in the manual or when Googling. Anyone can explain this for me?