Re: Object reference into variable?
| From: | Hamza Saglam | Date: | Tue, 07 Aug 2007 08:49:48 +0000 |
| Subject: | Re: Object reference into variable? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-260267@lists.php.net to get a copy of this message | ||
You may find the following article interesting. It talks about object
cloning, which I think what you are after...
http://www.phpfreaks.com/phpmanual/page/language.oop5.cloning.html
Regards,
Hamza.
""Sándor Tamás (GMail)"" <santasoft@gmail.com> wrote in message
news:003c01c7d8cd$8a84e910$3c646464@stgepe...
> Hello,
>
> I have a question (what a surprise :-) )
>
> I browsed the archives, but didn't find what I'm looking for.
> I have an object instance stored in some variable (like $myobject). I want
> to save this instance into another variable (like $tempobject). I thought,
> this will be the way:
> $myobject = new MyObject();
> $tempobject = $myobject;
> (or I tried this too:
> $tempobject = &$myobject)
>
> None of them worked, like I cannot access methods in the object:
> $tempobject->Foo()
> gives me an error: calling to method on a non-object variable.
>
> How can I tell PHP that $tempobject is a class instance of MyObject, and
> that I can use it's methods?
>
> Thanks,
> SanTa