Re: Re: Object reference into variable?

$tempobject *SHOULD* have been an object. Did you spell it right? Was $myobject an object in the first place? Start using var_dump() on all your data and see what's happening. On Tue, August 7, 2007 4:09 am, Sándor Tamás (GMail) wrote: > I forgot to tell you that I have to use PHP4.2 because of my web > provider. > Anything besides of _clone? > > SanTa > > ----- Original Message ----- > From: Hamza Saglam > To: "Sándor Tamás (GMail)" > Sent: Tuesday, August 07, 2007 10:49 AM > Subject: Re: Object reference into variable? > > > You may find the following article interesting. It talks about > object > cloning, which I think what you are after... > > > http://www.phpfreaks.com/phpmanual/page/language.oop5.cloning.html > > > Regards, > Hamza. > > > ""Sándor Tamás (GMail)"" <santasoft@gmail.com> wrote in message > news:003c01c7d8cd$8a84e910$3c646464@stgepe... > > Hello, > > > > I have a question (what a surprise :-) ) > > > > I browsed the archives, but didn't find what I'm looking for. > > I have an object instance stored in some variable (like > $myobject). I want > > to save this instance into another variable (like $tempobject). I > thought, > > this will be the way: > > $myobject = new MyObject(); > > $tempobject = $myobject; > > (or I tried this too: > > $tempobject = &$myobject) > > > > None of them worked, like I cannot access methods in the object: > > $tempobject->Foo() > > gives me an error: calling to method on a non-object variable. > > > > How can I tell PHP that $tempobject is a class instance of > MyObject, and > > that I can use it's methods? > > > > Thanks, > > SanTa > > > -- Some people have a "gift" link here. Know what I want? I want you to buy a CD from some indie artist. http://cdbaby.com/browse/from/lynch Yeah, I get a buck. So?