Re: how capture a parameter from a hyperlink and then pass it to the next

On Tue, 21 Nov 2000, Stinie Steinbach wrote: > I am trying to passing a parameter to my PHP program when the user > clicks on a hyperlink. I have tried syntax like: > > <td><a > > href=\"update.php3?id=$id\">$id<small>edit</small></a></td> > > if ik klik on the link is see the variable in the hyperlink and i can > open the right file the only problem i have is that i loos the variables > right on my way. . . > > does somone know what i do wrong??? > thanks :-) cf Unless you are echoing that line, you will see the variable's name in the link, not it's value. Do something like echo "<td><a href=\"update.php3?id=$id\">$id<small>edit</small></a></td>"; and assuming that a value has been assigned to $id it should show up in the link. You may need to use urlencode on the variable being passed. -- David Robley | WEBMASTER & Mail List Admin RESEARCH CENTRE FOR INJURY STUDIES | http://www.nisu.flinders.edu.au/ AusEinet | http://auseinet.flinders.edu.au/ Flinders University, ADELAIDE, SOUTH AUSTRALIA