Re: unsure how to do this any help appreciated

Michael Seton wrote: > To Whom this may Concern, > > Basically what im try to do is this.... (please bear with me im a php > noob) > require a remote file, if its blank then instead display a comment or > another file (which ever is easier) > > Example: > *_if > "http://launcher.worldofwarcraft.com/alert" contains > nothing or contains "Not Found" or "404 error", display " Sorry > no updates at this time or No server notices at this time" or > include blah.php, otherwise display > > _**_"http://launcher.worldofwarcraft.com/alert"._* > > > Because the source is remotely updated, the information contained at > this address is beyond my control, so i need this to control what is > said on my end > I'm not sure how to get this one to work > > Any help would be appreciated or a direction to where to find > something that will help me, > > Pixmyster > > Guild Master > Synergy Of Triumphalism > Horde - Spinebreaker - US Realm > World Of Warcraft Guild > Website: www.synergyoftriumphalism.com > Email: pixmyster@gmail.com > <?php $fp = fsockopen("launcher.worldofwarcraft.com", 80, $errno, $errstr, 30); //open the socket if (!$fp) // if the socket doesnt open, die die("$errstr ($errno)<br />\n"); //construct http specific headers $out = "GET /alert HTTP/1.1\r\n"; $out .= "Host: launcher.worldofwarcraft.com\r\n"; $out .= "Connection: Close\r\n\r\n"; $buff = ""; //generate a buffer to fille fwrite($fp, $out); //send the headers while (!feof($fp)) { $buff .= fgets($fp, 128); //read the response } fclose($fp); //close the socket if (strstr($buff, "404")) { //analyze. echo "no alerts"; } else { echo "alerts"; } ?> -- ================== Nick Stinemates (nick@stinemates.org) http://nick.stinemates.org AIM: Nick Stinemates MSN: nickstinemates@hotmail.com Yahoo: nickstinemates@yahoo.com ==================