preg_replace Question

Hi List I am trying to perform a number of replacements of place holders in an html page I am working on using preg_replace. I am stuck with a pronlem I can not work out and would appreciate some help. The code I have is as follows $html = preg_replace('/%Amount/',$amount,$html); $html is the source of a html page $amount is set earlier to a value read from a file When I view the html page the value of %Amount is not what I would expect. e.g $amount = $524.00 however only 4.00 is displayed in the %Amount field on the html page. I tried dropping the .00 from $amount to see if this might be a length issue and then %Amount was just 4 Am I doing something obviously wrong here? I have checked the php manual and I appear to be using preg_replace correctly. Regards, Richard Luckhurst Product Development Exodus Systems - Sydney, Australia. rluckhurst@resmaster.com Tel: (+612) 4751-9633 Fax: (+612) 4751-9644 Web: www.resmaster.com ================================================= Exodus Systems - Smarter Systems, Better Business =================================================