Re: check if any element of an array is not "empty"

From: Date: Wed, 30 Apr 2008 20:51:30 +0000
Subject: Re: check if any element of an array is not "empty"
References: 1  Groups: php.general 
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On Wed, Apr 30, 2008 at 2:36 PM, afan pasalic <afan@afan.net> wrote: > hi, > as a result of one calculation I'm receiving an array where elements > could be 0 or date (as string yyyy-mm-dd hh:ii:ss). > I have to check if any of elements of the array is "date" or if all > elements of the array is 0? > > If I try array_sum($result) I'll get 0 no matter what (0 + $string = 0). > > I know I can do something like: > foreach($result as $value) > { > if ($value !=0) > { > $alert = true; > } > } > > or > > if (in_array($result, '-')) > { > $alert = true; > } > > > but I was thinking if there is the function does that. i don think theres a function for that; and to be performance conscience, if just one occurrence of a date is all you need to know its not all 0's then break out of the loop once youve found that. foreach($result as $value) { if ($value !== 0) { $alert = true; break; } } -nathan

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