Re: check if any element of an array is not "empty"
| From: | Nathan Nobbe | Date: | Wed, 30 Apr 2008 20:51:30 +0000 |
| Subject: | Re: check if any element of an array is not "empty" | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-273743@lists.php.net to get a copy of this message | ||
On Wed, Apr 30, 2008 at 2:36 PM, afan pasalic <afan@afan.net> wrote:
> hi,
> as a result of one calculation I'm receiving an array where elements
> could be 0 or date (as string yyyy-mm-dd hh:ii:ss).
> I have to check if any of elements of the array is "date" or if all
> elements of the array is 0?
>
> If I try array_sum($result) I'll get 0 no matter what (0 + $string = 0).
>
> I know I can do something like:
> foreach($result as $value)
> {
> if ($value !=0)
> {
> $alert = true;
> }
> }
>
> or
>
> if (in_array($result, '-'))
> {
> $alert = true;
> }
>
>
> but I was thinking if there is the function does that.
i don think theres a function for that; and to be performance conscience, if
just one occurrence of a date is all you need to know its not all 0's then
break out of the loop once youve found that.
foreach($result as $value)
{
if ($value !== 0)
{
$alert = true;
break;
}
}
-nathan