Re: check if any element of an array is not "empty"
| From: | tedd | Date: | Fri, 02 May 2008 01:05:08 +0000 |
| Subject: | Re: check if any element of an array is not "empty" | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-273793@lists.php.net to get a copy of this message | ||
At 3:36 PM -0500 4/30/08, afan pasalic wrote:
hi, as a result of one calculation I'm receiving an array where elements could be 0 or date (as string yyyy-mm-dd hh:ii:ss). I have to check if any of elements of the array is "date" or if all elements of the array is 0? If I try array_sum($result) I'll get 0 no matter what (0 + $string = 0). I know I can do something like: foreach($result as $value) {You can create an empty array and check to see if the difference via array_diff. Cheers, tedd -- ------- http://sperling.com http://ancientstones.com http://earthstones.comif ($value !=0) { $alert = true; }} or if (in_array($result, '-')) {$alert = true;} but I was thinking if there is the function does that. thanks for any help. -afan