Re: syntax error
| From: | Aschwin Wesselius | Date: | Mon, 21 Jul 2008 11:55:31 +0000 |
| Subject: | Re: syntax error | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-277140@lists.php.net to get a copy of this message | ||
Eric Butera wrote:
On Mon, Jul 21, 2008 at 7:24 AM, Ronald Wiplinger <tm.ronald@gmail.com> wrote:Probably the mysql extension is not found or not loaded (due to not being compiled with the right path or the default path in PHP is not the right one). Happened to me a couple of times..... -- Aschwin Wesselius /'What you would like to be done to you, do that to the other....'/On a system with php4 and mysql 4.x I had these lines:Your mysql_connect is probably failing. Look at your error log or look at mysql_error() for a reason why.require("../db-config"); // includes $dbhost, $buname, $dbpass$db = mysql_connect($dbhost, $dbuname, $dbpass); mysql_select_db($dbname,$db); $sql = "SELECT * FROM CATEGORY WHERE ....."; $result = mysql_query($sql,$db); $num=mysql_num_rows($result); while ($myrow = mysql_fetch_array($result)) { .... Moving the *.php to a php5 and mysql 5.x site I get these errors: PHP Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in ... PHP Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in ... Looking at the manual, I cannot see what I am doing wrong. bye R.