Re: syntax error
| From: | Daniel Brown | Date: | Mon, 21 Jul 2008 21:51:58 +0000 |
| Subject: | Re: syntax error | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-277154@lists.php.net to get a copy of this message | ||
Please keep replies on list for all to benefit and be able to assist.
On Mon, Jul 21, 2008 at 5:47 PM, Ronald Wiplinger <tm.ronald@gmail.com> wrote:
>
> On Tue, Jul 22, 2008 at 1:51 AM, Daniel Brown <parasane@gmail.com> wrote:
>>
>> Try this:
>>
>> > $result = mysql_query($sql,$db) or die(mysql_error());
Did you try my suggestion above? If so, did you receive any errors?
> echo "result=$result<br>";
> $num=mysql_num_rows($result);
> echo "num=$num";
>
> I get:
>
> result=
> num=
The most you'd get from $result in this case would be a resource
identifier message, because that's all mysql_query() returns. And
since the resource link doesn't seem to be correctly established, $num
will be empty.
--
</Daniel P. Brown>
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