Re: PHP Question regarding include()

Paul, you need to echo out the variable, And you can't send variable like url's when including Try this instead, in main.php: $headertitle="homepage"; $headersection="home"; include("header.php"); in header.php: <title>Daniel's Website:<?=$headertitle; ?></title> ----- Original Message ----- From: "Paul Mullen" <pem@nellump.com> To: <janda2@dingoblue.net.au>; <php-general@lists.php.net> Sent: Wednesday, November 29, 2000 12:32 PM Subject: Re: [PHP] PHP Question regarding include() > >I current have: > > include("header.php?headertitle=homepage&headersection=home"); > >in index.php. This is so each content page can set the title and 'section' > >for the header of each page. > > > >and in header.php > > <title>Daniel's Website:<? $headertitle ?></title> > > Your method doesn't work (as you found out). Someone else on the list can > probably elaborate as to why. > > The contents of any included file are treated as if they were present in > the including document itself. Therefore, you can simply assign values to > the variables and then include the remote file: > > $headertitle = 'homepage'; > $headersection = 'home'; > include( 'header.php' ); > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > >