Re: PHP Question regarding include()

From: Date: Wed, 29 Nov 2000 11:42:41 +0000
Subject: Re: PHP Question regarding include()
References: 1  Groups: php.general 
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On Wed, 29 Nov 2000, janda2@dingoblue.net.au wrote: > I have been using PHP for a few weeks now and have found it very useful. I > am in the process of rewriting my website using PHP. > > I have a index.php, which imports a header.php and footer.php. But I want > to call header.php with some variables defined in index.php. i.e. > "header.php?title=homepage". > > I current have: > include("header.php?headertitle=homepage&headersection=home"); > in index.php. This is so each content page can set the title and 'section' > for the header of each page. > > and in header.php > <title>Daniel's Website:<? $headertitle ?></title> > > However when I load index.php in my web browser I get: Warning: Failed > opening 'header.php?headertitle=homepage&headersection=home' for inclusion > (include_path='.:/usr/local/lib/php') in > /home/daniel/public_html/new/index.php on line 2 > > I think I need to use another function, but due to the fact I am new to PHP > I am not sure what that would be, any assistance would be appreciated. > > Thanks, > > Daniel. Hi, The included code "sees" the variables of the surrounding code, therefore you can do: $headertitle=homepage; $headersection=home; include("header.php"); Cheers, Marco

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