Re: Dynamically creating multi-array field

No offense, but I thought it's obvious what I want to print. print_r() shows null, and it should print what you just wrote = array field. It works when first defining with eval(): eval('$tpl'.$node.'=array();'); I guess that's the only way. Anyway, I appreciate your quick reply, Martin Jim Lucas napsal(a):

Martin Zvarík wrote:

PHP Version 5.2.4 <? $node = '[5][1][]'; ${'tpl'.$node} = 'some text'; print_r($tpl); // null ?> I really don't like to use the EVAL function, but do I have choice?? This sucks.

You should print the results that you are looking for! Are you looking for something like this? Array (

    [5] => Array
        (
            [1] => Array
                (
                    [0] => some text
                )

        )

) how is the $node string being created?