Re: Dynamically creating multi-array field
| From: | Martin Zvarík | Date: | Mon, 27 Oct 2008 05:19:11 +0000 |
| Subject: | Re: Dynamically creating multi-array field | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-282466@lists.php.net to get a copy of this message | ||
Nope, you have to use the eval() everytime for read/write.
Martin Zvarík napsal(a):
No offense, but I thought it's obvious what I want to print. print_r() shows null, and it should print what you just wrote = array field. It works when first defining with eval(): eval('$tpl'.$node.'=array();'); I guess that's the only way. Anyway, I appreciate your quick reply, Martin Jim Lucas napsal(a):Martin Zvarík wrote:PHP Version 5.2.4 <? $node = '[5][1][]'; ${'tpl'.$node} = 'some text'; print_r($tpl); // null ?> I really don't like to use the EVAL function, but do I have choice?? This sucks.You should print the results that you are looking for! Are you looking for something like this? Array ([5] => Array ( [1] => Array ( [0] => some text ))) how is the $node string being created?