Re: passing array in form HELP!

Use the Serialize and Deserialize functions ----- Original Message ----- From: "Joe Stump" <joe@earth.care2.com> To: "John Hanson" <jhanson@a440studios.com> Cc: <php-general@lists.php.net> Sent: Monday, December 04, 2000 4:20 PM Subject: Re: [PHP] passing array in form HELP! > Do this: > > if(!is_array($var)) > { > if(strlen($var)) > { > $var = explode(',',$var); > } > else > { > $var = array(); > } > } > > if(!sizeof($var)) > { > $var = array('Joe','Schmoo','Foo','Bar'); > } > > > echo '<INPUT TYPE="hidden" NAME="var" VALUE="'.implode(',',$var).'">'."\n"; > > > On Mon, Dec 04, 2000 at 03:13:58PM -0600, John Hanson wrote: > > I can not get an array to pass in a form as a hidden variable! It allways returns a string. > > I want to pass additional info in a form (not info in the form itself) with POST method > > This is what I'm doing: > > > > IN FORM------> > > $info=array("first_name"=>"John", > > "middle_init"=>"R", > > "last_name"=>"Hanson"); > > > > echo "<input type=\"hidden\" name=\"info\" > > value=\"".$info."\">"; > > > > IN 2nd PAGE----> > > $info=$HTTP_POST_VARS["info"]; > > > > THIS LINE; > > echo "info is=>".gettype($info); > > > > PRINTS ---> > > info is=>sring > > > > WHY IS IT A STRING?? > > > > > > > > > > ----- > Joe Stump, PHP Hacker > joestump98@yahoo.com > http://www.miester.org/ > > Need a programmer? > http://www.google.com/search?q=%22Joe+Stump%22 > ***************************************************************** > * RENT THIS SPACE - SEEN BY THOUSANDS EACH DAY! * > * Current Sponsor: http://www.smackdown.com > * > ***************************************************************** > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >