Re: Passing an undetermined amount of arguments by reference
| From: | Jay Moore | Date: | Wed, 04 Feb 2009 20:23:17 +0000 |
| Subject: | Re: Passing an undetermined amount of arguments by reference | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-287636@lists.php.net to get a copy of this message | ||
Jim Lucas wrote:
Jay Moore wrote:Will that work properly? $a = "'hello'"; $b = "sup"; $c = "\\hola'"; $d = array($a, $b, $c); escape($id, $d); JayGreetings list. Say I have a function that escapes a string before being passed to MySQL like so: function escape($id, &$string) {Use an array as an alternate method of sending/returning data to the second argument. function escape($id, &$data) { if ( is_array($data) ) { foreach ( $data AS $k => $v ) { escape($id, $v); $data[$k] = $v; } } else { $data = mysql_real_escape_string($data, $id); } } This would handle any number of nested arrays/datasets. Hope it helps.$string }