Re: Passing an undetermined amount of arguments by reference

From: Date: Wed, 04 Feb 2009 20:33:52 +0000
Subject: Re: Passing an undetermined amount of arguments by reference
References: 1 2 3 4  Groups: php.general 
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Shawn McKenzie wrote:
Jay Moore wrote:
Jim Lucas wrote:
Jay Moore wrote:
Greetings list. Say I have a function that escapes a string before being passed to MySQL like so: function escape($id, &$string) {
    $string }
Use an array as an alternate method of sending/returning data to the second argument. function escape($id, &$data) {
    if ( is_array($data) ) {
        foreach ( $data AS $k => $v ) {
            escape($id, $v);
            $data[$k] = $v;
        }
    } else {
        $data = mysql_real_escape_string($data, $id);
    }
} This would handle any number of nested arrays/datasets. Hope it helps.
Will that work properly? $a = "'hello'"; $b = "sup"; $c = "\\hola'"; $d = array($a, $b, $c); escape($id, $d); Jay
I would try: $d = compact('a', 'b', 'c');
What is the difference? Please excuse my naivety. :) Jay

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