Re: password field validation

From: Date: Thu, 12 Mar 2009 19:40:31 +0000
Subject: Re: password field validation
References: 1 2 3  Groups: php.general 
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Afan Pasalic schreef: > > > Andrew Ballard wrote: >> On Thu, Mar 12, 2009 at 3:05 PM, Jason Todd Slack-Moehrle >> <mailinglists@mailnewsrss.com> wrote: >> >>> Hi All, >>> >>> I have an input field with type="password". >>> >>> I am trying to do some error checking to see if the user puts a value in >>> after they submit the form (i.e not left it blank) >>> >>> Here is what I have: >>> >>> on form: >>> Password: <input id="PASSWORD" name="PASSWORD" >>> type="password" >>> size="15"> >>> >>> In PHP error checking: >>> >>> if (empty($_POST[PASSSWORD])) >>> { $GERROR="TRUE";} >>> >>> even though I am putting characters in the field before I submit I am >>> always >>> getting TRUE returned. >>> >>> This same tactic works for other fields I have that I need to make >>> sure they >>> put values in, just I have never done this before with a password field. >>> >>> What am I doing wrong? I just want to make sure they put something >>> there! >>> >>> -Jason >>> >> >> If that's a direct copy/paste from your actual code, there is an extra >> S in PASSWORD. Also, you should enclose the array key in quotes: >> >> if (empty($_POST['PASSWORD'])) >> { $GERROR='TRUE'; } >> >> >> Andrew >> >> > > try if trim() gives you any different result: > > if (empty(trim($_POST['PASSWORD']))) > { $GERROR='TRUE'; } definitely gives a different result. $ php -r ' > $r = " "; var_dump(empty(trim($r)));' PHP Fatal error: Can't use function return value in write context in Command line code on line 2 you can only pass variables to empty() *not* expressions. > > afan > > >

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