Re: password field validation

Jochem Maas wrote:

Afan Pasalic schreef:

Andrew Ballard wrote:

    
On Thu, Mar 12, 2009 at 3:05 PM, Jason Todd Slack-Moehrle

<mailinglists@mailnewsrss.com> wrote:

      
Hi All,

I have an input field with type="password". I am trying to do some error checking to see if the user puts a value in after they submit the form (i.e not left it blank) Here is what I have: on form: Password: <input id="PASSWORD" name="PASSWORD" type="password" size="15"> In PHP error checking: if (empty($_POST[PASSSWORD])) { $GERROR="TRUE";} even though I am putting characters in the field before I submit I am always getting TRUE returned. This same tactic works for other fields I have that I need to make sure they put values in, just I have never done this before with a password field. What am I doing wrong? I just want to make sure they put something there! -Jason

If that's a direct copy/paste from your actual code, there is an extra S in PASSWORD. Also, you should enclose the array key in quotes: if (empty($_POST['PASSWORD'])) { $GERROR='TRUE'; } Andrew

try if trim() gives you any different result: if (empty(trim($_POST['PASSWORD']))) { $GERROR='TRUE'; }

definitely gives a different result. $ php -r '

$r = " "; var_dump(empty(trim($r)));'

PHP Fatal error: Can't use function return value in write context in Command line code on line 2 you can only pass variables to empty() *not* expressions. :-) yup... didn't think that way... though, I was giving an idea $password = trim($_POST['PASSWORD']); if (empty($password) { $GERROR='TRUE'; } ;-)