Re: Function Question

Hi Jeff! Try... <?php function displayMe ($string, $number = '', $name = 'Bob Villa') { $a = "$string $name the $number<br>"; return $a; } $z = array ('Sux doeth'); echo displayMe ($z[0] ); ?> good luck Marcelo Gulin Jeff Lacy escribió: > Hello World, > I have a question about functions and arrays. Assume I have a script > like so: > > <?php > function displayMe ($string, $number = '', $name = 'Bob Villa') { > $a = "$string $name the $number<br>"; > return $a; > } > > $z = array ('Sux doeth'); > > echo displayMe ($z[0], $z[1], $z[2]); > ?> > > I would be much happier if this printed 'Sux doeth Bob Villa the<br>', > but it doesn't. > It comes back with 'Sux doeth the <br>'. Is there an easy way around this, > or do I have to use an if? Thanks a bunch, everyone! > > Cheers :-) > > Jeff > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net