Select and compare problems still ...
| From: | Miller, Terion | Date: | Wed, 01 Jul 2009 14:56:07 +0000 |
| Subject: | Select and compare problems still ... | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-294794@lists.php.net to get a copy of this message | ||
Why doesn't this work?
$query = "SELECT * FROM
restaurants WHERE name ='$ucName' AND
address = '$ucAddress' " ;
$result = mysql_query($query) or die(mysql_error());
echo $result;
$row = mysql_fetch_array ($result);
$sql = "INSERT INTO restaurants (name, address, inDate, inType, notes,
critical, cviolations, noncritical) VALUES (" ;
$sql .= " '$ucName',
'$ucAddress', '$inDate', '$inType', '$notes',
'$critical',
'$cleanViolations', '$noncritical')";
$result = mysql_query($sql) or die(mysql_error());
The error I keep getting is:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use
And I have gone in the mySQL panel and let it make the query ....so I'm
really stumped why it hangs ...