Re: Select and compare problems still ...

On Jul 1, 2009, at 10:56 AM, "Miller, Terion" <tmiller@springfi.gannett.com

wrote:

Why doesn't this work? $query = "SELECT * FROM restaurants WHERE name ='$ucName' AND address = '$ucAddress' " ; $result = mysql_query($query) or die(mysql_error()); echo $result;

    $row = mysql_fetch_array ($result);

$sql = "INSERT INTO restaurants (name, address, inDate, inType, notes, critical, cviolations, noncritical) VALUES (" ;

    $sql .= " '$ucName',

'$ucAddress', '$inDate', '$inType', '$notes', '$critical', '$cleanViolations', '$noncritical')";

       $result = mysql_query($sql) or die(mysql_error());

The error I keep getting is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use And I have gone in the mySQL panel and let it make the query ....so I'm really stumped why it hangs ... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

Try removing the backticks from the tablename, I have found that if you include the backticks around the table name and not the field names, mysql will throw the occassional fit. Bastien Sent from my iPod