Re: Replace in a string with regex

rszeus wrote: > Thank you. > > What about instead test i want to insert a variable ? > Like > $id = "30"; > $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; > echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', '$1$id$3', > $file); Sure that can be done. But you will need to change the second argument to have double quotes so it will be parsed by PHP. Then I would surround YOUR variable with curly brackets to separate it from the rest. echo preg_replace('#(screens/)temp/.+?_1(_main\.jpg)#', "$1{$id}$3", $file); > I am confusing " and '. > > Thank you > > > -----Mensagem original----- > De: Eddie Drapkin [mailto:oorza2k5@gmail.com] > Enviada: quarta-feira, 22 de Julho de 2009 14:12 > Para: rszeus > Cc: php-general@lists.php.net > Assunto: Re: [PHP] Replace in a string with regex > > On Wed, Jul 22, 2009 at 9:07 AM, rszeus<rszeus@gmail.com> wrote: >> Hi. It Works to remove the _1 but it doesn't replace >> '7a45gfdi6icpan1jtb1j99o925' for 'test' >> >> Thank you >> >> -----Mensagem original----- >> De: Eddie Drapkin [mailto:oorza2k5@gmail.com] >> Enviada: quarta-feira, 22 de Julho de 2009 13:11 >> Para: rszeus >> Cc: php-general@lists.php.net >> Assunto: Re: [PHP] Replace in a string with regex >> >> On Wed, Jul 22, 2009 at 8:02 AM, rszeus<rszeus@gmail.com> wrote: >>> Hello, >>> >>> I’m tryng to make some replacements on a string. >>> >>> Everything goês fine until the regular expression. >>> >>> >>> >>> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; >>> >>> echo $a = str_replace(array(7a45gfdi6icpan1jtb1j99o925, >>> 'temp/',’_([0-9])’), array(“test”,"",””), $file) >>> >>> >>> >>> The idea is to remove /temp and the last _1 from the file name..but i’m only >>> getting this: >>> >>> screens/test_1_main.jpg >>> >>> >>> >>> I want it to be: screens/test_main.jpg >>> >>> >>> >>> Thank you >>> >>> >>> >>> >> If you're trying to do a regular expression based search and replace, >> you probably ought to use preg_replace instead of str_replace, as >> str_replace doesn't parse regular expressions. >> >> Try this one out, I think I got what you wanted to do: >> >> <?php >> >> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; >> >> echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', '$1$2$3', >> $file); >> >> > > In the second parameter, $2 is the string you'd want to replace to > test so change '$1$2$3' to '$1test$3'. > > It seems like you're having trouble with regular expressions, may I > suggest you read up on them? > > http://www.regular-expressions.info/ is a pretty great free > resource, > as ridiculous as the design is. > >