Re: Replace in a string with regex

On Wed, Jul 22, 2009 at 11:01 AM, Ashley Sheridan<ash@ashleysheridan.co.uk> wrote: > On Wed, 2009-07-22 at 07:54 -0700, Jim Lucas wrote: >> rszeus wrote: >> > Thank you. >> > >> > What about instead test i want to insert a variable ? >> > Like >> > $id = "30"; >> > $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; >> > echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', >> > '$1$id$3', $file); >> >> Sure that can be done.  But you will need to change the second argument >> to have double quotes so it will be parsed by PHP. >> >> Then I would surround YOUR variable with curly brackets to separate it >> from the rest. >> >> echo preg_replace('#(screens/)temp/.+?_1(_main\.jpg)#', >>                   "$1{$id}$3", >>                   $file); >> >> > I am confusing " and '. >> > >> > Thank you >> > >> > >> > -----Mensagem original----- >> > De: Eddie Drapkin [mailto:oorza2k5@gmail.com] >> > Enviada: quarta-feira, 22 de Julho de 2009 14:12 >> > Para: rszeus >> > Cc: php-general@lists.php.net >> > Assunto: Re: [PHP] Replace in a string with regex >> > >> > On Wed, Jul 22, 2009 at 9:07 AM, rszeus<rszeus@gmail.com> wrote: >> >> Hi. It Works to remove the _1 but it doesn't replace >> >> '7a45gfdi6icpan1jtb1j99o925' for 'test' >> >> >> >> Thank you >> >> >> >> -----Mensagem original----- >> >> De: Eddie Drapkin [mailto:oorza2k5@gmail.com] >> >> Enviada: quarta-feira, 22 de Julho de 2009 13:11 >> >> Para: rszeus >> >> Cc: php-general@lists.php.net >> >> Assunto: Re: [PHP] Replace in a string with regex >> >> >> >> On Wed, Jul 22, 2009 at 8:02 AM, rszeus<rszeus@gmail.com> wrote: >> >>> Hello, >> >>> >> >>> I’m tryng to make some replacements on a string. >> >>> >> >>> Everything goês fine until the regular expression. >> >>> >> >>> >> >>> >> >>> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; >> >>> >> >>> echo $a =  str_replace(array(7a45gfdi6icpan1jtb1j99o925, >> >>> 'temp/',’_([0-9])’), array(“test”,"",””), >> >>> $file) >> >>> >> >>> >> >>> >> >>> The idea is to remove /temp and the last _1 from the file name..but i’m only >> >>> getting this: >> >>> >> >>> screens/test_1_main.jpg >> >>> >> >>> >> >>> >> >>> I want it to be: screens/test_main.jpg >> >>> >> >>> >> >>> >> >>> Thank you >> >>> >> >>> >> >>> >> >>> >> >> If you're trying to do a regular expression based search and replace, >> >> you probably ought to use preg_replace instead of str_replace, as >> >> str_replace doesn't parse regular expressions. >> >> >> >> Try this one out, I think I got what you wanted to do: >> >> >> >> <?php >> >> >> >> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; >> >> >> >> echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', >> >> '$1$2$3', $file); >> >> >> >> >> > >> > In the second parameter, $2 is the string you'd want to replace to >> > test so change '$1$2$3' to '$1test$3'. >> > >> > It seems like you're having trouble with regular expressions, may I >> > suggest you read up on them? >> > >> > http://www.regular-expressions.info/ is a pretty great >> > free resource, >> > as ridiculous as the design is. >> > >> > >> >> >> > I tested this, with the double quotes and the curly braces around the > middle argument (to avoid PHP getting confused) and it didn't recognise > the matches by the numbered $1, $3, etc. I know I'm not the op who asked > the original question, but it might help him/her? > > Thanks > Ash > www.ashleysheridan.co.uk > > To avoid confusion, rather than something like "$1{$id}$3" Which looks really indecipherable, I'd definitely think something like '$1' . $id . '$3' is a lot easier to read and understand what's going on by immediately looking at it. As an added bonus, it'll definitely work ;)