Re: isset not functioning
| From: | Andrew Ballard | Date: | Mon, 03 Aug 2009 17:13:10 +0000 |
| Subject: | Re: isset not functioning | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-296213@lists.php.net to get a copy of this message | ||
On Mon, Aug 3, 2009 at 1:08 PM, Allen McCabe<allenmccabe@gmail.com> wrote:
> I created a simple survey for my work website, most of the PHP is on my
> process.php document, which is referenced by a form on a seperate page
> containing the form with the method of "post".
>
> On my process.php page, the script obtains the field data using the
> $_REQUEST[] function.
>
> I have a small if statement to check to see if they filled out the
> 'firstname' field, and if they did not, to replace $name with "Sir or
> Madam". Unfortunately, $name always equals "Sir or Madam", wether a value
> for "firstname" was entered or not.
>
> All the of the other instances of using $_REQUEST[] functions just fine, but
> don't make use of if or isset. Here is the code snippet:
>
> if(isset($_REQUEST['firstname']) && !empty($RESULT['firstname'])) {
> $name = $_REQUEST['firstname'];
> } else {
> $name = 'Sir or Madam';
> }
>
> I also tried adding an underscore to $RESULT (I got the code for this from a
> php.net comment on the manual), to make it $_RESULT, but this doesn't seem
> to be a pre-set function, and it still does not make it work. I am guessing
> the user neglected to define $RESULT in his snippet, or I overlooked it.
>
> Can anyone see any problems with the code?
>
You are switching from $_REQUEST to $RESULT. Trying to use $_RESULT
won't make it any better.
Andrew