Re: isset not functioning

From: Date: Mon, 03 Aug 2009 17:13:10 +0000
Subject: Re: isset not functioning
References: 1  Groups: php.general 
Request: Send a blank email to php-general+get-296213@lists.php.net to get a copy of this message
On Mon, Aug 3, 2009 at 1:08 PM, Allen McCabe<allenmccabe@gmail.com> wrote: > I created a simple survey for my work website, most of the PHP is on my > process.php document, which is referenced by a form on a seperate page > containing the form with the method of "post". > > On my process.php page, the script obtains the field data using the > $_REQUEST[] function. > > I have a small if statement to check to see if they filled out the > 'firstname' field, and if they did not, to replace $name with "Sir or > Madam". Unfortunately, $name always equals "Sir or Madam", wether a value > for "firstname" was entered or not. > > All the of the other instances of using $_REQUEST[] functions just fine, but > don't make use of if or isset. Here is the code snippet: > > if(isset($_REQUEST['firstname']) && !empty($RESULT['firstname'])) { >  $name = $_REQUEST['firstname']; >  } else { >  $name = 'Sir or Madam'; > } > > I also tried adding an underscore to $RESULT (I got the code for this from a > php.net comment on the manual), to make it $_RESULT, but this doesn't seem > to be a pre-set function, and it still does not make it work. I am guessing > the user neglected to define $RESULT in his snippet, or I overlooked it. > > Can anyone see any problems with the code? > You are switching from $_REQUEST to $RESULT. Trying to use $_RESULT won't make it any better. Andrew

« previous php.general (#296213) next »