Re: isset not functioning

From: Date: Mon, 03 Aug 2009 17:11:44 +0000
Subject: Re: isset not functioning
References: 1  Groups: php.general 
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Your if-statement should be like this: [code] if(isset($_REQUEST['firstname']) && !empty($_REQUEST['firstname'])) { ... } [/code] -- --- Contact info: Skype: parham-d MSN: fire_lizard16 at hotmail dot com email: parham90 at GMail dot com "Allen McCabe" <allenmccabe@gmail.com> wrote in message news:657acef20908031008nc2c29cdo3e13733bc6f29d1a@mail.gmail.com... >I created a simple survey for my work website, most of the PHP is on my > process.php document, which is referenced by a form on a seperate page > containing the form with the method of "post". > > On my process.php page, the script obtains the field data using the > $_REQUEST[] function. > > I have a small if statement to check to see if they filled out the > 'firstname' field, and if they did not, to replace $name with "Sir or > Madam". Unfortunately, $name always equals "Sir or Madam", wether a value > for "firstname" was entered or not. > > All the of the other instances of using $_REQUEST[] functions just fine, > but > don't make use of if or isset. Here is the code snippet: > > if(isset($_REQUEST['firstname']) && !empty($RESULT['firstname'])) { > $name = $_REQUEST['firstname']; > } else { > $name = 'Sir or Madam'; > } > > I also tried adding an underscore to $RESULT (I got the code for this from > a > php.net comment on the manual), to make it $_RESULT, but this doesn't seem > to be a pre-set function, and it still does not make it work. I am > guessing > the user neglected to define $RESULT in his snippet, or I overlooked it. > > Can anyone see any problems with the code? >

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