Re: How to output a NULL field?
| From: | Bastien Koert | Date: | Tue, 25 Aug 2009 18:17:04 +0000 |
| Subject: | Re: How to output a NULL field? | ||
| References: | 1 2 3 4 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-297207@lists.php.net to get a copy of this message | ||
On Tue, Aug 25, 2009 at 2:00 PM, David Stoltz<Dstoltz@shh.org> wrote:
> $rs->Fields(22) equals a NULL in the database
>
> My Code:
>
> if(empty($rs->Fields(22))){
> $q4 = "";
> }else{
> $q4 = $rs->Fields(22);
> }
>
> Produces this error:
> Fatal error: Can't use method return value in write context in
> D:\Inetpub\wwwroot\evaluations\lookup2.php on line 32
>
> Line 32 is the "if" line...
>
> If I switch the code to (using is_null):
> if(is_null($rs->Fields(22))){
> $q4 = "";
> }else{
> $q4 = $rs->Fields(22);
> }
>
> It produces this error:
> Catchable fatal error: Object of class variant could not be converted to
> string in D:\Inetpub\wwwroot\evaluations\lookup2.php on line 196
>
> Line 196 is: <?php echo $q4;?>
>
> What am I doing wrong?
>
> Thanks!
>
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>
>
$q4 = '' . $rs->Fields(22);
Note that it's two single quotes
--
Bastien
Cat, the other other white meat