Re: How to output a NULL field?

Com function is just for Windows,I don't kown why some body like use it.:( 2009/8/27 Andrew Ballard <aballard@gmail.com>: > On Wed, Aug 26, 2009 at 9:51 AM, David Stoltz<Dstoltz@shh.org> wrote: >> Sorry - I don't know what you mean by DB class? >> >> I'm using Microsoft SQL 2000....with this code: >> >> <?php >> //create an instance of the  ADO connection object >> $conn = new COM ("ADODB.Connection") >>  or die("Cannot start ADO"); >> //define connection string, specify database driver >> $connStr = "PROVIDER=SQLOLEDB;SERVER=xxxx;UID=xxx;PWD=xxxx;DATABASE=xxxx"; >> $conn->open($connStr); //Open the connection to the database >> >> $query = "SELECT * FROM eval_evaluations WHERE id = ".$_POST["eval"]; >> >> $rs = $conn->execute($query); >> >> echo $rs->Fields(22); //this is where that particular field is NULL, and produces the >> error >> >> .... >> > > Because you are using COM, you can't use PHP's empty(), isset(), or > is_null() in your if(...) statement. I've not used COM for much in > PHP, but I think you'll have to do something like this: > > switch (variant_get_type($rs->Fields(22)) { >    case VT_EMPTY: >    case VT_NULL: >        $q4 = ''; >        break; > >    case VT_UI1: >