Re: Change styling depending on var value

To add to what Ashley said about $row[3], remember that when you are returning from the db the counter for fields will start at 0 not 1, so if its the 3rd field that will be $row[2]. You might also want to do switch rather then elseif but thats always a good debate. On Fri, Nov 20, 2009 at 3:16 PM, Ashley Sheridan <ash@ashleysheridan.co.uk>wrote: > On Fri, 2009-11-20 at 15:11 -0500, Phil Matt wrote: > > > Ashley Sheridan wrote: > > > > > Well, you're main problem here is that you are only using a single = > > > character. What that is saying to PHP is: "if you let me assign the > > > value of $beverage to $row[3] then do this next bit", but what I think > > > you wanted it to say was "if $row[3] is the same as $beverage then do > > > this next bit", which would need == instead of = > > > > > > > Thanks, Ashley. I don't do enough PHP to get used to the syntax. > > > > I changed the operators to ==, but my conditional apparently isn't > > working correctly. I checked to make sure the values in the cells were > > the strings as I've specified them, but the resultant formatting always > > defaults to the ELSE color. > > > > Must be something very simple, but I'm just not getting it. > > > > Cheers --- Phil > > > Don't forget to reply to all! > > Just a quick question, what do you get if you do: > > print $row[3]; > > Does it contain a string like you expect? > > Thanks, > Ash > http://www.ashleysheridan.co.uk > > >