Re: Change styling depending on var value

Mari Masuda wrote:

This may be a dumb question, but did you actually fetch the db query's results and put them in $row before trying to use $row? In MySQL you could do something like: $query = "select * from my_table"; $result = mysql_query($query); $row = mysql_fetch_array($result); //this statement would need to be inside of a loop if there is more than one result Thanks, Mari. That was it: I usually declare the variables first, then on with the rest of the code. I had inserted the $row conditional values right after the vars, before the rest of the query...just plain dumb.

Cheers --- Phil