Re: php on the Command line

> i understand how argv and argc work, but if someone leaves off a > required field, or something such as a password , is it possible to stop > and prompt them ? i know no perl or c, and im fairly efficent in php, so > i'd like to stick with this. You could just do something as simple as: if ($argc != 3) { die("usage: scriptname username password database"); } else { list($Username, $Password, $Database) = $argv; } If you want the user to be able to enter a value, try using fgets on stdin (See the fopen() docs for instructions on how to open stdin, stdout, or stderr). It should be somewhat like this: $stdout = fopen("php://stdout"); $stdin = fopen("php://stdin"); fputs($stdout, "Username: "); fgets($stdin, $Username);